3x(2x+1)=2(3x^2-6)

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Solution for 3x(2x+1)=2(3x^2-6) equation: 


Simplifying
3x(2x + 1) = 2(3x2 + -6)

Reorder the terms:
3x(1 + 2x) = 2(3x2 + -6)
(1 * 3x + 2x * 3x) = 2(3x2 + -6)
(3x + 6x2) = 2(3x2 + -6)

Reorder the terms:
3x + 6x2 = 2(-6 + 3x2)
3x + 6x2 = (-6 * 2 + 3x2 * 2)
3x + 6x2 = (-12 + 6x2)

Add '-6x2' to each side of the equation.
3x + 6x2 + -6x2 = -12 + 6x2 + -6x2

Combine like terms: 6x2 + -6x2 = 0
3x + 0 = -12 + 6x2 + -6x2
3x = -12 + 6x2 + -6x2

Combine like terms: 6x2 + -6x2 = 0
3x = -12 + 0
3x = -12

Solving
3x = -12

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '3'.
x = -4

Simplifying
x = -4

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